Answer
$ 2$
Work Step by Step
$sin\frac{\pi}{2}-tan\frac{19\pi}{4}\\=1-tan(4\pi+\frac{3\pi}{4})\\=1-tan(\pi-\frac{\pi}{4})\\=1+tan(\frac{\pi}{4})\\=1+1=2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Chapter Test - Page 460: 11
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