Answer
$-\frac{5\sqrt {146}}{146}$.
Work Step by Step
Given point $(-5,11)$ in quadrant II, we have $x=-5, y=11$, thus $r=\sqrt {(-5)^2+(11)^2}=\sqrt {146}$ and $cos\theta=\frac{x}{r}=-\frac{5\sqrt {146}}{146}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Chapter Test - Page 460: 23
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