Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Test - Page 460: 18

Answer

$-\dfrac{3}{5}$

Work Step by Step

Since the trigonometric function $\sin$ is an odd function, we can write $f(-\theta)=-f(\theta) \implies \sin{-a}=-\sin a$. We have: $f(x)=\sin x $ and $f(a)=\dfrac{3}{5}$ Therefore, $f(-a) =\sin (-a) =-\sin a=-\dfrac{3}{5}$
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