Answer
$x=1-\ln{5}$
Work Step by Step
We are given that $e^{1-x}=5$
Take $\ln$ of both sides to obtain:
$\ln{e^{1-x}}=\ln{5}\\1-x=\ln{5}\\1=x+\ln{5}$
Therefore, we get: $x=1-\ln{5}$
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