Answer
The first four terms are: $\ln 3, 2 \ln 3, 3 \ln 3, 4 \ln 3$
The sequence is arithmetic with a common difference of $\ln (3)$ .
Work Step by Step
We need to substitute $1, 2, 3,$ and $4$ for $n$ into the given equation to find the first four terms.
Recall: Logarithmic property $\ln (a^n)=n \ln a$
$s_1=\ln (3^1)=\ln 3$
$s_2=\ln (3^2)=2 \ln 3$
$s_3=\ln (3^3)=3 \ln 3$
$s_4=\ln (3^4)=4 \ln 3$
We can see that the terms increase by $\ln (3)$. Thus, the sequence is arithmetic with a common difference of $\ln (3)$.
