Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 98

Answer

quotient$=x^2-\frac{2}{3}x-\frac{1}{9}$, remainder$=\frac{16}{9}x-\frac{17}{9}$

Work Step by Step

1. Use long division to get quotient$=x^2-\frac{2}{3}x-\frac{1}{9}$, remainder$=\frac{16}{9}x-\frac{17}{9}$ 2. We have $(x^2-\frac{2}{3}x-\frac{1}{9})(3x^2+x+1)+(\frac{16}{9}x-\frac{17}{9})=3x^4-x^3+x-2$
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