Answer
$2x^2-3y^2+xy$
Work Step by Step
By using the FOIL (First, Outer, Inner, Last) method of multiplying two binomials, we have
$$
(2x + 3y)(x - y)= 2x^2 -2xy+3xy-3y^2 \\
= 2x^2-3y^2+xy
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 62
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