Answer
$4x-3+\frac{ x+1}{x^2}$
Work Step by Step
By dividing each term of the polynomial by $x^2$, we have
$$
\frac{4x^3-3x^2+x+1}{x^2}=4x-3+\frac{ x+1}{x^2}.$$
Checking:
$$
x^2(4x-3)+ x+1=4x^3-3x^2+x+1
.$$
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