Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 77

Answer

$ x^2-y^2$

Work Step by Step

We distribute to obtain: $$ (x + y)(x - y)= x^2-xy+xy-y^2=x^2-y^2 .$$ Note that this is the difference of two squares formula: $(a-b)(a+b)=a^2-b^2$
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