Answer
see graph; $(-3,0)$ and $(3,0)$
Work Step by Step
Step 1. Given equations $x^2-y^2=9$ and $x^2+y^2=9$, we can graph both equations as shown in the figure.
Step 2. We can identify two intersect points $(-3,0)$ and $(3,0)$ as solutions to the system.
Step 3. Check the solutions with the first equation: we have $(-3)^2-(0)^2=9$ and $(3)^2-(0)^2=9$
Step 4. Check the solutions with the second equation: we have $(-3)^2+(0)^2=9$ and $(3)^2+(0)^2=9$
