Answer
see graph; $(-2,0)$ and $(2,0)$
Work Step by Step
Step 1. Given equations $x^2-y^2=4$ and $x^2+y^2=4$, we can graph both equations as shown in the figure.
Step 2. We can identify two intersection points $(-2,0)$ and $(2,0)$ as solutions to the system.
Step 3. Check the solutions with the first equation: we have $(-2)^2-(0)^2=4$ and $(2)^2-(0)^2=4$
Step 4. Check the solutions with the second equation: we have $(-2)^2+(0)^2=4$ and $(2)^2+(0)^2=4$
