Answer
see graph; domain $[-3.3]$, range $[-4,4]$
Work Step by Step
Step 1. From the given equation $\frac{(x)^2}{9}+\frac{(y)^2}{16}=1$, we have $a=4, b=3, c=\sqrt {a^2-b^2}=\sqrt {7}$ centered at $(0,0)$ with a vertical major axis.
Step 2. We can find the vertices as $(0,\pm4),(\pm3,0)$, foci as $(0,\pm\sqrt {7})$
Step 3. We can graph the equation as shown in the figure with domain $[-3.3]$ and range $[-4,4]$
