Answer
See graph; domain $(-\infty,-3]\cup[3,\infty)$, range $(-\infty,\infty)$
Work Step by Step
Step 1. From the given equation $\frac{(x)^2}{9}-\frac{(y)^2}{16}=1$, we have $a=3, b=4, c=\sqrt {a^2+b^2}=5$ centered at $(0,0)$ with a horizontal transverse axis.
Step 2. We can find the vertices as $(\pm3,0)$, foci as $(\pm5,0)$, and asymptotes as $y=\frac{b}{a}(x)$ or $y=\pm\frac{4}{3}(x)$
Step 3. We can graph the equation as shown in the figure with domain $(-\infty,-3]\cup[3,\infty)$ and range $(-\infty,\infty)$
