Answer
$\frac{x^2}{9}-\frac{y^2}{55}=1$
Work Step by Step
Step 1. From the given conditions, we have $c=8, a=3$; thus $b=\sqrt {8^2-3^2}=\sqrt {55}$ with center at $(0,0)$ and foci on $y=0$
Step 2. We can write the equation as $\frac{x^2}{9}-\frac{y^2}{55}=1$