Answer
See graph. Foci $(\pm5,0)$; asymptotes $y=\pm\frac{3}{4}x$
Work Step by Step
Step 1. Rewrite the given equation as $\frac{x^2}{16}-\frac{y^2}{9}=1$; we have $a=4, b=3$ and thus $c=\sqrt {4^2+3^2}=5$. The foci are on the x-axis.
Step 2. See graph; we can locate the foci at $(\pm5,0)$
Step 3. The asymptotes can be found as $y=\pm\frac{3}{4}x$
