Answer
See graph. Foci $(0,\pm\sqrt {17})$; asymptotes $y= \pm4x$
Work Step by Step
Step 1. From the given equation, we have $a=4, b=1$; thus $c=\sqrt {4^2+1^2}=\sqrt {17}$ the foci are on the y-axis.
Step 2. See graph; we can locate the foci at $(0,\pm\sqrt {17})$
Step 3. The asymptotes can be found as $y=\pm\frac{4}{1}x=\pm4x$
