Answer
See graph: foci $(2\pm\sqrt {41},-3)$, asymptotes $y=\pm\frac{4}{5}(x-2)-3$
Work Step by Step
Step 1. From the given equation, we have $a=5, b=4$; thus $c=\sqrt {5^2+4^2}=\sqrt {41}$ and the center is at $(2,-3)$
Step 2. See graph; we can locate the foci at $(2\pm\sqrt {41},-3)$
Step 3. The asymptotes can be found as $y+3=\pm\frac{4}{5}(x-2)$ or $y=\pm\frac{4}{5}(x-2)-3$
