Answer
See graph: foci $(3, -2\pm\sqrt {41})$, asymptotes $y=\pm\frac{5}{4}(x-3)-2$
Work Step by Step
Step 1. From the given equation, we have $a=5, b=4$; thus $c=\sqrt {5^2+4^2}=\sqrt {41}$ and the center is at $(3,-2)$ with foci on $x=3$.
Step 2. See graph; we can locate the foci at $(3, -2\pm\sqrt {41})$
Step 3. The asymptotes can be found as $y+2=\pm\frac{5}{4}(x-3)$ or $y=\pm\frac{5}{4}(x-3)-2$
