Answer
$(-2,-3)$, $(2,-3)$, $(-3,2)$, $(3,2)$
Work Step by Step
Re-arrange the given two equations and then use the substitution method to get
$x^2+(x^2-7)^2=13$
or, $x^4-13x^2+36=0$
This gives: $(x+2)(x-2)(x+3)(x-3)=0$
when $x=-2$ then we have $y=(-2)^2 -7=-3$
when $x=2$ then we have $y=(2)^2 -7=-3$
when $x=-3$ then we have $y=(-3)^2 -7=2$
when $x=3$ then we have $y=(3)^2 -7=2$
Hence, our answers are: $(-2,-3)$, $(2,-3)$, $(-3,2)$, $(3,2)$
