Answer
$(-3,-1)$, $(1,3)$
Work Step by Step
Re-arrange the given two equations and then use the substitution method to get
$x^2+(x+2)^2=10$
or, $x^2+2x-3=0$
This gives: $(x+3)(x-1)=0$
when $x=-3$ then we have $y=-1$
when $x=1$ then we have $y=3$
Hence, our answers are: $(-3,-1)$, $(1,3)$
