Answer
$(\dfrac{5}{2},\dfrac{-7}{2})$, $(0,-1)$
Work Step by Step
Re-arrange the given two equations and then use the substitution method to get
$(-y-1)^2+y^2+6y-(-y-1)=-5$
or, $2y^2+9y+7=0$
This gives: $(2y+7)(y+1)=0$
when $y=\dfrac{-7}{2}$ then we have $y=\dfrac{5}{2}$
when $y=-1$ then we have $x=0$
Hence, our answers are: $(\dfrac{5}{2},\dfrac{-7}{2})$, $(0,-1)$
