Answer
$(0,1)$, $(-3,4)$
Work Step by Step
Re-arrange the given two equations and then use the substitution method to get
$x+(x^2+2x+1)=1$
or, $x^2+3x=0$
or, $x(x+3)=0$
when $x=0$ then we have $y=(0)^2+2(0)+1=1$
when $x=-3$ then we have $y=(-3)^2+2(-3)+1=4$
Hence, our answers are: $(0,1)$, $(-3,4)$
