Answer
$(1,2)$, $(9,6)$
Work Step by Step
Re-arrange the given two equations and then use the substitution method to get
$x=2y-3$
Now, $y^2=4(2y-3)$
or, $y^2-8y+12 =0$
This gives: $(y-2)(y-6)=0$
when $y=2$ then we have $x=1$
when $y=6$ then we have $x=9$
Hence, our answers are: $(1,2)$, $(9,6)$
