Answer
There is no triangle possible with the provided measurements.
Work Step by Step
Use the ratio $\frac{a}{\sin A}$ or $\frac{9.3}{\sin 18{}^\circ }$.
Now, use the law of sines to find B.
$\begin{align}
& \frac{b}{\sin B}=\frac{a}{\sin A} \\
& \frac{9.3}{\sin 18{}^\circ }=\frac{41}{\sin B} \\
& \sin B=\frac{41\sin 18{}^\circ }{9.3} \\
& B\approx 1.36
\end{align}$
As the sine ratio can never exceed 1, there is no angle B for which $\sin B=1.36$.
There is no triangle with the provided measurements.
