Answer
a. $p=sin(2t)$
b. No.
Work Step by Step
a. Simplify the function as
$p=3sin(2t)+2sin(2t+\pi)=3sin(2t)+2(sin(2t)cos(\pi)+cos(2t)sin(\pi))=3sin(2t)-2sin(2t)=sin(2t)$
b. No, because our amplitude is $1$, not $0$.
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