Answer
$15.9\ ft$
Work Step by Step
Given the elevation angle $\theta=53^\circ $ and a horizontal distance (run) of 12 feet, we have $tan\theta=\frac{rise}{run}$ and $tan53^\circ=\frac{h}{12}$ where $h$ is the height of the flagpole. Solving for $h$, we have $h=12tan53^\circ\approx15.9\ ft$
