Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Cumulative Review Exercises - Page 709: 15

Answer

$\frac{16\pi}{9}\approx5.59\ rad$

Work Step by Step

As $1^\circ=\frac{\pi}{180}\ rad$, we have $320^\circ=320\times\frac{\pi}{180}=\frac{16\pi}{9}\approx5.59\ rad$
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