Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Cumulative Review Exercises - Page 709: 13

Answer

$-\frac{\sqrt 2}{2}$

Work Step by Step

Step 1. Write $225^\circ=180^\circ+45^\circ=\pi+\frac{\pi}{4}$ Step 2. Using the Addition Formula, we have $sin(225^\circ)=sin(\pi)cos(\frac{\pi}{4})+cos(\pi)sin(\frac{\pi}{4})=-\frac{\sqrt 2}{2}$
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