Answer
Using the logarithm, we have $x-1=log_{11}(125)=\frac{log125}{log11}\approx2.0136$; thus $x=1+\frac{log125}{log11}\approx3.01$
Work Step by Step
$1+\frac{log125}{log11}\approx3.0136$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Cumulative Review Exercises - Page 709: 2
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