Answer
$f(x)=(0.6)^{x}=(\frac{3}{5})^{x}$
$(-2,\frac{25}{9})$, $(-1,\frac{5}{3})$, $(1,\frac{3}{5})$, $(2,\frac{9}{25})$
Graph is attached
Work Step by Step
$f(x)=(0.6)^{x}=(\frac{3}{5})^{x}$
Lets put $x=-2,-1,1,2$
$f(-2) = (\frac{3}{5})^{-2} = \frac{25}{9}$
$f(-1) = (\frac{3}{5})^{-1} = \frac{5}{3}$
$f(1) = (\frac{3}{5})^{1} = \frac{3}{5}$
$f(2) = (\frac{3}{5})^{2} = \frac{9}{25}$
Plot the set of points
