Answer
$(-2,9)$, $(-1,3)$, $(1,\frac{1}{3})$, $(2,\frac{1}{9})$
Graph is attached
Work Step by Step
$h(x)=(\frac{1}{3})^{x}$
Lets put $x=-2,-1,1,2$
$g(-2) = (\frac{1}{3})^{-2} = 9$
$g(-1) = (\frac{1}{3})^{-1} = 3$
$g(1) = (\frac{1}{3})^{1} = \frac{1}{3}$
$g(2) = (\frac{1}{3})^{2} = \frac{1}{9}$
Plot the set of points
