Answer
$(-4,\frac{16}{81})$, $(-2,\frac{4}{9})$, $(-1,\frac{2}{3})$, $(1,\frac{3}{2})$, $(2,\frac{9}{4})$, $(4,\frac{81}{16})$
Graph is attached
Work Step by Step
$f(x) = (\frac{3}{2})^{x}$
Lets put $x=-4,-2,-1,1,2,4$
$f(-4) = (\frac{3}{2})^{-4} = \frac{16}{81}$
$f(-2) = (\frac{3}{2})^{-2} = \frac{4}{9}$
$f(-1) = (\frac{3}{2})^{-1} = \frac{2}{3}$
$f(1) = (\frac{3}{2})^{1} = \frac{3}{2}$
$f(2) = (\frac{3}{2})^{2} = \frac{9}{4}$
$f(4) = (\frac{3}{2})^{4} = \frac{81}{16}$
Plot the set of points
