Answer
$(-4,\frac{81}{256})$, $(-2,\frac{9}{16})$, $(-1,\frac{3}{4})$, $(1,\frac{4}{3})$, $(2,\frac{16}{9})$, $(4,\frac{256}{81})$
Graph is attached
Work Step by Step
$g(x) = (\frac{4}{3})^{x}$
Lets put x=−4,−2,−1,1,2,4
$g(-4) = (\frac{4}{3})^{-4} = \frac{81}{256}$
$g(-2) = (\frac{4}{3})^{-2} = \frac{9}{16}$
$g(-1) = (\frac{4}{3})^{-1} = \frac{3}{4}$
$g(1) = (\frac{4}{3})^{1} = \frac{4}{3}$
$g(2) = (\frac{4}{3})^{2} = \frac{16}{9}$
$g(4) = (\frac{4}{3})^{4} = \frac{256}{81}$
Plot the set of points
