Answer
$ x\approx 0.99$
Work Step by Step
$ 9e^{5x}=1269\qquad $...divide both sides with 9
$ e^{5x}=141\qquad $ ... apply $\ln $( ) to both sides
$\ln e^{5x}=\ln 141\qquad $ ... apply basic property, $\log_{b}b^{x}=x $
$ 5x=\ln 141\qquad $...divide both sides with 5
$ x=\displaystyle \frac{\ln 141}{5}\qquad $... round to two decimal places
$ x\approx 0.99$
