Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 512: 46

Answer

$4x^{2}$

Work Step by Step

$10^{x}$ and $\log x $ are inverse functions, meaning that $ 10^{\log(x)}=x\qquad $ and $\qquad \log(10^{x})=x $ --- Thus, $10^{\log(4x^{2})}=4x^{2}$
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