Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 512: 39

Answer

See the graph below:

Work Step by Step

Let us draw the graph of $ f\left( x \right)=\log x $ as follows: Construct the table of coordinates for $ f\left( x \right)={{\log }}x $ and choose the appropriate values for $ x $ and calculate the corresponding $ y\text{-values}$. Also, plot every point provided in the above table and join them using a smooth curve, and the $ y\text{-axis}$ or $ x=0$ is the vertical asymptote. Now, the curve of $ g\left( x \right)=-\log \left( x+3 \right)$ is obtained by translating the graph of $ f\left( x \right)=\log x $ to the left by 3 units and then taking a reflection about the $ x\text{-axis}$. So, the graph will be $ g\left( x \right)=-\log \left( x+3 \right)$ and we plot $ f\left( x \right)=\log x $ in the same rectangular plane. In the above graph: Vertical asymptote is $ x=0$ Domain is $\left( -\infty,0 \right)$ And the range is $\left( -\infty,\infty \right)$ of the function $ f\left( x \right)=\log x $ The vertical asymptote is $ x=0$, Domain is $\left( -3,\infty \right)$ The range is $\left( -\infty,\infty \right)$ of the function $ g\left( x \right)=-\log \left( x+3 \right)$.
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