Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 512: 23

Answer

$\log_{17}17=1.$

Work Step by Step

$\log_{b}x=y $ is equivalent to $ b^{y}=x $ --- $\log_{17}17=y \quad $ is equivalent to $ \quad 17^{y}=17$. Now, since $17^{1}=17,$ it follows that $ y=1$ and $\quad \log_{17}17=1.$
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