Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 512: 44

Answer

$6x $

Work Step by Step

$\log_{b}x=y $ is equivalent to $ b^{y}=x.\qquad (*)$ Consequently,$\qquad \log_{b}b^{x}=x.\qquad (**)$ --- The natural logarithm has base e, $\ln e^{6x}=\log_{e}e^{6x}\qquad $ ... apply (**) = $6x $
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