Answer
No solution
Work Step by Step
Use the rule $\log (p q)=\log p+\log q $ with $ p=x+4$ and $ q=x+1$ to obtain
$\ln[(x+4)(x+1)]=2 \ln (x+3)$
Simplify:
$(x+3)^2=(x+4)(x+1)$
$ x^2+6x+9=x^2+5x+4$
or, $ x+9=5x+4 \implies x=-5$
But $ x=-5$ is not in the domain.
Thus, our result is: No solution
