Answer
The solution of the equation is $-1+2i\,\,\,or\,\,\,-1-2i$.
Work Step by Step
Comparing the provided equation with the general quadratic equation, we get
$a=1,b=2\,\,\text{ and }\,\,c=5$
Substitute the value of $a,b\,\,\text{ and }\,\,c$ in the formula $x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$, to get
$\begin{align}
& x=\frac{-2\pm \sqrt{{{2}^{2}}-4\cdot 1\cdot 5}}{2\cdot 1} \\
& =\frac{-2\pm \sqrt{4-20}}{2} \\
& =\frac{-2\pm 4i}{2} \\
& =-1\pm 2i \\
& =-1+2i\,\,\,or\,\,\,-1-2i
\end{align}$
Therefore, the solution of the equation is $-1+2i\,\,\,or\,\,\,-1-2i$.
