Answer
See below:
Work Step by Step
Let us draw the graph of the function $f\left( x \right)={{\left( x-2 \right)}^{2}}\left( x+1 \right)$ as follows:
Find the $x-\text{intercept}$ and $y\text{-intercept}$:
The $x-\text{intercept}s$ are as follows:
Take $y=0$ ,
$0={{\left( x-2 \right)}^{2}}\left( x+1 \right)$
${{\left( x-2 \right)}^{2}}=0$ or $x+1=0$
$x=2$ And $x=-1$
So, the $x-\text{intercepts}$ are $\left( 2,0 \right)$ and $\left( -1,0 \right)$.
And the $y\text{-intercept}$ is as follows:
$y=0$
Use the intercepts to sketch the graph.
