Answer
$ x=3$
Work Step by Step
Use the rule $\log (p q)=\log p+\log q $ with $ p=x+5$ and $ q=x-1$ to obtain
$\log_{2}(x+5)(x-1)=4$
Simplify:
$(x+5)(x-1)=2^4$
$ x^2+4x-5 =16$
or, $(x+7)(x-3)$
So, $ x=-7, 3$, but $ x=-3$ is not in the domain.
Thus, our result is: $ x=3$
