Answer
quotient $2x^2+x+6$ and remainder $r(x)=\frac{-38}{x+3}$
Work Step by Step
Step 1. Using long division as shown in the figure, we can obtain $\frac{2x^3+7x^2+9x-20}{x+3}=2x^2+x+6+\frac{-38}{x+3}$
Step 2. We can identify the quotient as $2x^2+x+6$ and the remainder as $r(x)=\frac{-38}{x+3}$
