Answer
quotient $2x^2+3x+5$ and remainder $r(x)=0$
Work Step by Step
Step 1. Using long division as shown in the figure, we can obtain $\frac{6x^3+17x^2+27x+20}{3x+4}=2x^2+3x+5+\frac{0}{3x+4}$
Step 2. We can identify the quotient as $2x^2+3x+5$ and the remainder as $r(x)=0$
