Answer
quotient $x^3+3x^2+9x+27$ and remainder $r(x)=\frac{0}{x-3}$
Work Step by Step
Step 1. Using long division as shown in the figure, we can obtain $\frac{x^4-81}{x-3}=x^3+3x^2+9x+27+\frac{0}{x-3}$
Step 2. We can identify the quotient as $x^3+3x^2+9x+27$ and the remainder as $r(x)=\frac{0}{x-3}$
