Answer
quotient $2x+5$ and remainder $r(x)=0$
Work Step by Step
Step 1. Using long division as shown in the figure, we can obtain $\frac{6x^3+14x^2-11x-15}{3x^2-x-3}=2x+5+\frac{0}{3x^2-x-3}$
Step 2. We can identify the quotient as $2x+5$ and the remainder as $r(x)=0$
