Answer
quotient $2x-3$ and remainder $r(x)=\frac{3}{2x-1}$
Work Step by Step
Step 1. Using long division as shown in the figure, we can obtain $\frac{4x^2-8x+6}{2x-1}=2x-3+\frac{3}{2x-1}$
Step 2. We can identify the quotient as $2x-3$ and the remainder as $r(x)=\frac{3}{2x-1}$
