Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.3 - Limits and Continuity - Exercise Set - Page 1161: 25

Answer

The function $ f\left( x \right)=\pi $ is not discontinuous for any number.

Work Step by Step

Consider the rational function $ f\left( x \right)=\pi $, Here, $ p\left( x \right)=\pi \text{ and }q\left( x \right)=1$ Find the zeros of the function $ q\left( x \right)=1$ by $ q\left( x \right)=0$, $1=0$ Which cannot be possible, Thus, $1\ne 0$ There is no zero of the function $ q\left( x \right)=1$. Thus, the function $ f\left( x \right)=\pi $ is not discontinuous for any number.
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