Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 36

$x^{34}+17x^{32}+136x^{30}$

Calculate the first three terms of $(x^2+1)^{17}$ by using Binomial Theorem or Binomial expansion. This implies $(x^2+1)^{17}=\displaystyle \binom{17}{0}(x^2)^{17}1^0+\displaystyle \binom{17}{1}(x^2)^{16}1^1+\displaystyle \binom{17}{2}(x^2)^{15}1^2$ or, $=x^{34}+17(x^{32})(1)+136x^{30}(1)$ or, $=x^{34}+17x^{32}+136x^{30}$