Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.5 - The Binomial Theorum - Exercise Set - Page 1092: 34

Answer

$x^{9}-18x^8y+144x^7y^2$

Work Step by Step

Calculate the first three terms of $(x-2y)^{9}$ by using Binomial Theorem or Binomial expansion. This implies $(x-2y)^{9}=\displaystyle \binom{9}{0}(x)^{9}(-2y)^0+\displaystyle \binom{9}{1}(x)^{8}(-2y)^1+\displaystyle \binom{9}{2}(x)^{7}(-2y)^2$ or, $=x^{9}+(9)x^8(-2y)+(36)x^7(4y^2)$ or, $=x^{9}-18x^8y+144x^7y^2$
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